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गणित · कक्षा 9

Area of Trapeziums and Compound Shapes

The area of a trapezium as half the sum of the parallel sides times the height; splitting a compound shape into rectangles and triangles and adding or subtracting areas.

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इस वीडियो के अध्याय
  1. 0:00 Area of Trapeziums and Compound Shapes
  2. 1:37 Example 1: Find the area of the trapezium ABCD.
  3. 2:15 Example 2: The area of trapezium PQRS is 72 cm². Find its p…
  4. 2:57 Example 3: Find the area of this compound shape.
  5. 3:30 Example 4: Find the area of the symmetric trapezium ABCD.
  6. 4:02 Example 5: The area of the trapezium ABCD is 36 cm². Find i…
  7. 4:53 Example 6: Find the area of the compound shape.
  8. 5:41 Example 7: The diagram shows a trapezium ABCD with parallel…
  9. 6:19 Common mistakes
  10. 6:39 Try it
  11. 6:54 Try it: Find the total area of the shape by using a subtrac…
  12. 7:18 Area of Trapeziums and Compound Shapes

आप क्या सीखेंगे

  • Calculate the area of a trapezium using the formula involving the parallel sides and the perpendicular height.
  • Deconstruct complex compound shapes into standard geometric figures such as rectangles, triangles, and trapeziums to calculate total area.
  • Apply additive and subtractive methods to determine the area of shaded or composite regions in plane geometry.

व्याख्या

Introduction to Two-Dimensional Area and Units

Area is the measure of the extent of a two-dimensional surface or region enclosed within a boundary, expressed in square units such as cm2 or m2. Before examining complex figures, recall that the area of a rectangle is calculated by multiplying its length by its breadth, and the area of a triangle is half the product of its base and its perpendicular height. When shapes become more irregular or consist of multiple distinct polygons joined together, direct application of basic formulas is no longer sufficient. Instead, mathematicians rely on geometric decomposition, breaking large figures into simpler standard shapes whose areas are easy to compute. This principle of conservation of area states that the total area of a non-overlapping composite shape is equal to the sum of the areas of its individual constituent parts. Furthermore, area can also be found by subtraction, where a smaller shape is excised from a larger enclosing frame, a technique particularly useful for frames, borders, and complex cutouts. Mastering these foundational principles allows learners to tackle any polygon, including trapeziums and irregular compound shapes, with systematic precision.

The Structure and Area Formula of a Trapezium

A trapezium, known in some regions as a trapezoid, is a convex quadrilateral that possesses at least one pair of parallel sides. The two parallel sides are designated as the bases of the trapezium, while the non-parallel sides are known as the legs. The perpendicular distance measured between the two parallel bases is called the height or altitude of the trapezium. To find the area of a trapezium, one can visualize the shape being divided into two distinct triangles by drawing a diagonal from one vertex to the opposite non-adjacent vertex. If a trapezium has parallel sides of lengths a and b, and a perpendicular height h, drawing a diagonal splits the trapezium into two triangles. Both triangles share the same height h, while their bases are a and b respectively. The area of the first triangle is 1/2 times a times h, and the area of the second triangle is 1/2 times b times h. Adding these two triangular areas together yields 1/2 times a times h plus 1/2 times b times h. Factoring out the common terms 1/2 and h produces the standard algebraic formula for the area of a trapezium, which is A equals 1/2 multiplied by the sum of a and b, all multiplied by h. This formula can also be interpreted conceptually as multiplying the average length of the two parallel sides by the perpendicular height. It is vital that the height used in the calculation is measured perpendicularly to the parallel bases, not along the slant length of the non-parallel legs.

Worked Examples for Trapeziums

Consider a trapezium designated as PQRS where the side PQ is parallel to the side SR. Let the length of base PQ be 8 cm, the length of base SR be 12 cm, and the perpendicular height measured from SR to PQ be 5 cm. To calculate the area of trapezium PQRS, substitute these known values into the trapezium area formula. The sum of the parallel sides is 8 cm plus 12 cm, which equals 20 cm. Multiplying this sum by the height of 5 cm gives 100 cm2. Halving this product results in an area of 50 cm2. For a second example, consider a trapezium ABCD where AB is parallel to DC. In this scenario, let AB equal 7 cm, DC equal 11 cm, and the area is given as 54 cm2. To find the perpendicular height h of this trapezium, first add the parallel sides: 7 cm plus 11 cm equals 18 cm. Substitute the known values into the area equation: 54 equals 1/2 multiplied by 18 multiplied by h. Simplify the right side by taking half of 18, which gives 9. The equation simplifies to 54 equals 9 multiplied by h. Dividing both sides by 9 yields h equals 6 cm. This demonstrates that the formula can be rearranged algebraically to find an unknown dimension when the total area and other parameters are provided.

Compound Shapes and Additive Area Methods

A compound shape, often referred to as a composite shape, is a geometric figure made up of two or more simple shapes combined together. To find the total area of a compound shape using the additive method, the figure must be partitioned into non-overlapping standard shapes such as rectangles, squares, triangles, and trapeziums. Each constituent shape is identified, its necessary dimensions are extracted from the diagram, and its individual area is calculated using the appropriate formula. Finally, all the individual areas are summed to obtain the total area of the compound shape. When dividing a compound shape, teachers and learners must ensure that no gaps exist between the partitions and that no regions overlap, as overlapping would lead to double-counting of area. Every required length must be accounted for by using given dimensions or by deducing missing lengths through the addition and subtraction of parallel boundary measurements. For instance, if a compound shape consists of a rectangle surmounted by a triangle, the total area is simply the area of the rectangle plus the area of the triangle.

Subtractive Area Methods and Complex Boundaries

Not all compound shapes are evaluated by adding parts together; many practical geometric problems require the subtractive method. This technique involves calculating the area of a larger, outer enclosing shape and subtracting the areas of any internal holes, cutouts, or missing sections. Consider a rectangular sheet of metal that has a smaller rectangular hole cut out from its center. The area of the remaining metal is found by calculating the area of the outer rectangle and subtracting the area of the inner rectangle. This subtractive approach is essential for calculating the area of borders, picture frames, annular rings, and composite floor plans where rooms or structural pillars are omitted from the total footprint. When applying the subtractive method, it is critical to clearly define the outer boundary and identify the exact dimensions of every internal cutout. Care must be taken to ensure that units are consistent throughout the calculation before subtraction is performed.

Worked Examples for Compound Shapes

Consider a compound shape formed by joining a rectangle and a triangle along a shared edge. Let the shape be ABCDEF, configured such that AFED is a rectangle and FBE is an isosceles triangle sitting on top of edge FE. Let the length of AD be 10 cm and the length of AB be 6 cm, making AFED a rectangle with dimensions 10 cm by 6 cm. The edge FE is part of the rectangle and has a length of 10 cm. The triangle FBE has base FE equal to 10 cm, and its perpendicular height from vertex B to the base FE is 4 cm. To find the total area of compound shape ABCDEF, first calculate the area of rectangle AFED by multiplying length AD by width AB, which equals 10 cm multiplied by 6 cm, yielding 60 cm2. Next, calculate the area of triangle FBE using the formula 1/2 times base times height, which is 1/2 multiplied by 10 cm multiplied by 4 cm, yielding 20 cm2. Adding the area of the rectangle and the area of the triangle gives 60 cm2 plus 20 cm2, resulting in a total compound area of 80 cm2. For a second worked example involving subtraction, consider a large square garden plot measuring 15 metres on each side, inside of which there is a rectangular swimming pool measuring 8 metres long and 4 metres wide. To find the area of the grass surrounding the pool, first calculate the area of the outer square by squaring its side length: 15 multiplied by 15 equals 225 m2. Next, calculate the area of the rectangular pool: 8 multiplied by 4 equals 32 m2. Subtract the pool area from the garden area: 225 m2 minus 32 m2 equals 193 m2. Thus, the area of the grass is 193 m2.

Common Misconceptions in Area Calculations

Learners frequently encounter difficulties when calculating areas of trapeziums and compound shapes due to persistent misunderstandings. One common error is using the slant height of a trapezium instead of its perpendicular height when applying the area formula. The slant height is longer than the perpendicular height, and substituting it leads to an inflated and incorrect area calculation. Another frequent mistake occurs when learners fail to recognize that compound shapes can be partitioned in multiple valid ways; some believe there is only one correct way to slice a shape, causing confusion when their partition lines differ from a peer's. Additionally, students often confuse perimeter with area, attempting to add up boundary lengths when calculating surface coverage, or multiplying lengths incorrectly across inconsistent units such as mixing centimeters and meters. Ensuring all dimensions are converted to the same unit before calculation and always verifying that height measurements form a ninety-degree angle with the base prevents these errors.

मुख्य शब्द

Trapezium
A convex quadrilateral that has at least one pair of parallel sides.
Compound Shape
A geometric figure made up of two or more simple shapes combined together.
Perpendicular Height
The shortest distance between two parallel lines, measured at a right angle.
Conservation of Area
The principle that the total area of a non-overlapping composite shape equals the sum of its individual parts.
Additive Method
A technique for finding the area of a compound shape by summing the areas of its partitioned constituent parts.
Subtractive Method
A technique for finding the area of a shape by calculating an outer area and subtracting internal cutouts.

हल किए गए उदाहरण

1Find the area of a trapezium whose parallel bases measure 14 cm and 10 cm, and whose perpendicular height is 6 cm.

हल दिखाएँ

Step 1: Identify the given values from the problem statement. Base a = 14 cm, base b = 10 cm, and perpendicular height h = 6 cm. Reason: Extracting known parameters for the trapezium area formula.

Step 2: State the formula for the area of a trapezium. Area = 1/2 multiplied by (a plus b) multiplied by h. Reason: Standard formula for trapezium surface measurement.

Step 3: Substitute the known values into the formula. Area = 1/2 multiplied by (14 plus 10) multiplied by 6. Reason: Replacing algebraic variables with numerical values.

Step 4: Add the lengths of the parallel bases inside the brackets. 14 plus 10 equals 24. Reason: Evaluating parentheses according to order of operations.

Step 5: Multiply the sum by the height. 24 multiplied by 6 equals 144. Reason: Combining the linear sum with the perpendicular dimension.

Step 6: Multiply by 1/2 to find the final area. 144 multiplied by 1/2 equals 72. Reason: Halving the composite rectangular product.

Step 7: State the final answer with correct units. The area of the trapezium is 72 cm2. Reason: Area is expressed in square units.

2A shape consists of a rectangle measuring 12 cm by 5 cm with a triangle attached along the 12 cm side. The triangle has a perpendicular height of 3 cm from the shared base. Calculate the total area of the compound shape.

हल दिखाएँ

Step 1: Identify the constituent parts of the compound shape. The figure is made of a rectangle and a triangle sharing a 12 cm edge. Reason: Deconstructing the compound shape into standard geometric components.

Step 2: Calculate the area of the rectangle. Length = 12 cm, width = 5 cm. Area of rectangle = length multiplied by width = 12 multiplied by 5 = 60 cm2. Reason: Standard formula for the area of a rectangle.

Step 3: Calculate the area of the triangle. Base = 12 cm, height = 3 cm. Area of triangle = 1/2 multiplied by base multiplied by height = 1/2 multiplied by 12 multiplied by 3. Reason: Standard formula for the area of a triangle.

Step 4: Evaluate the triangle area calculation. 1/2 multiplied by 12 equals 6. Then 6 multiplied by 3 equals 18 cm2. Reason: Performing multiplication and halving operations.

Step 5: Apply the additive method by summing the individual areas. Total area = Area of rectangle plus Area of triangle = 60 plus 18 = 78 cm2. Reason: Conservation of area states that non-overlapping parts sum to the total area.

Step 6: State the final answer. The total area of the compound shape is 78 cm2. Reason: Combining solved parts into final dimensional units.

आम ग़लतफ़हमियाँ

ग़लतफ़हमी Learners often use the slant height of a trapezium in the area formula instead of the perpendicular height.

असल में The formula requires the perpendicular height because area measures flat surface coverage at right angles; slant height is longer and will produce an incorrect result.

ग़लतफ़हमी Students believe that a compound shape must be split into sections in only one specific way to be solved correctly.

असल में A compound shape can be partitioned into different combinations of triangles and rectangles, and as long as no gaps or overlaps occur, the final total area will always be the same.

ग़लतफ़हमी Learners confuse area with perimeter, adding side lengths together when asked to find the space inside a shape.

असल में Perimeter is the total linear distance around the outside of a shape, whereas area measures the two-dimensional surface units enclosed within that boundary.

पाठ्यक्रम से मेल

CBSE Mathematics (Class 6-10)

  • 9:U5:01 Areas