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गणित · कक्षा 8, 9

Gradient and Intercept of a Straight Line

Reading gradient and y-intercept from a graph and from y = mx + c, and writing the equation of a line from its features.

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इस वीडियो के अध्याय
  1. 0:00 Gradient and Intercept of a Straight Line
  2. 1:17 Example 1: Find the equation of the straight line with a gr…
  3. 2:20 The graph of y = 3x + 5
  4. 2:29 Example 2: Find the gradient and y-intercept of the line gi…
  5. 3:43 The lines cross at (0, 4)
  6. 3:54 Example 3:
  7. 4:40 Example 4: A line passes through the points A(0, 3) and B(4…
  8. 6:17 The lines cross at (0, 3)
  9. 6:29 Common mistakes
  10. 6:55 Try it
  11. 7:15 Try it: Find the equation of the straight line with gradien…
  12. 7:48 The lines cross at (0, -2)
  13. 8:02 Gradient and Intercept of a Straight Line

आप क्या सीखेंगे

  • Identify and calculate the gradient of a straight line from a graph using a right-angled triangle.
  • Determine the y-intercept of a straight line from its graphical representation.
  • Interpret the parameters m and c in the linear equation y = mx + c.
  • Write the equation of a straight line given its gradient and y-intercept, or from a graph.

व्याख्या

Introduction to Linear Relationships

Linear relationships appear constantly in mathematics and everyday life whenever two quantities change together at a constant rate. For example, if a car travels at a steady speed of sixty kilometres per hour, the distance travelled increases by a fixed amount for every single hour that passes. When such a relationship is plotted on a Cartesian coordinate plane, the resulting points form a straight line. Investigating this straight line requires understanding two fundamental numerical properties: how steep the line is, and where the line crosses the vertical axis.

Every straight line on the coordinate plane can be described using an algebraic equation containing two variables, usually x and y. The variable x represents the horizontal coordinate, and the variable y represents the vertical coordinate. The simplest straight lines are horizontal or vertical, but most lines slant upwards or downwards as they move from left to right. To analyse any sloped line completely, two pieces of geometric information are necessary: the gradient, which measures the steepness and direction of the slope, and the y-intercept, which marks the exact height where the line intersects the vertical y-axis. Grasping these two concepts transforms a simple geometric drawing into a powerful algebraic tool, allowing predictions and calculations about the underlying real-world scenario.

Understanding the Gradient

The gradient of a straight line measures its steepness and whether it rises or falls from left to right. Formally, the gradient is defined as the change in the vertical coordinate divided by the change in the horizontal coordinate between any two distinct points on the line. This ratio is often summarised in mathematical language as rise over run. To calculate the gradient of a line from a graph, one must select two points where the line crosses the grid intersections cleanly. By drawing a right-angled triangle underneath or above the line between these two points, the vertical height of the triangle gives the rise, and the horizontal width gives the run.

When a line slopes upwards from left to right, the vertical coordinate increases as the horizontal coordinate increases, resulting in a positive gradient. When a line slopes downwards from left to right, the vertical coordinate decreases as the horizontal coordinate increases, resulting in a negative gradient. A horizontal line has a zero gradient because the rise is zero regardless of the run. A vertical line has an undefined gradient because the run is zero, meaning division by zero occurs, which is mathematically impossible. The numerical value of the gradient dictates the rate of change; a gradient of three means that for every single unit moved to the right, the line moves three units upwards. A fractional gradient, such as one over two, indicates a gentler slope where the line moves up by one unit for every two units moved to the right. Calculating this value accurately forms the foundation of coordinate geometry.

Finding the Y-Intercept

The y-intercept of a straight line is the exact point where the line crosses the vertical axis, known as the y-axis. At this specific location, the horizontal coordinate x is always equal to zero. Identifying the y-intercept from a graph is a straightforward visual task: one simply looks at the vertical axis and finds the coordinate where the line intersects it. This value is conventionally denoted by the letter c in algebraic expressions.

The y-intercept acts as the starting value or initial position of the linear relationship. For instance, if a linear model describes the total cost of hiring a plumber, the y-intercept represents the fixed call-out fee charged before any hours of work begin. If the line passes through the origin, which is the point zero comma zero, the y-intercept is zero, meaning there is no initial value. When examining an equation in the standard linear form, the constant term that stands alone without an x attached is always the y-intercept. Understanding both the gradient and the y-intercept allows any straight line to be fully categorised and reconstructed algebraically.

The Equation of a Straight Line: y = mx + c

The equation y = mx + c is the standard slope-intercept form for the equation of a straight line. In this universal formula, y represents the vertical coordinate of any point on the line, and x represents the horizontal coordinate of that same point. The letter m stands for the gradient of the line, determining its steepness and direction. The letter c stands for the y-intercept, determining where the line crosses the vertical axis. Any linear equation can be rearranged into this exact format to reveal its key geometric features instantly.

Given the gradient and the y-intercept of a line, writing its equation is a direct substitution task. If a line has a gradient of four and a y-intercept of negative two, substituting these values into the template yields the equation y = 4x - 2. Conversely, if an equation is presented in a different arrangement, such as 2x + y = 6, algebraic manipulation is required to isolate y on the left side. Subtracting 2x from both sides transforms the equation into y = -2x + 6, immediately exposing a gradient of negative two and a y-intercept of positive six. This algebraic flexibility allows mathematicians to switch effortlessly between visual graphs and algebraic formulas.

Worked Examples

Applying the concepts of gradient and y-intercept requires methodical steps, whether reading from a graph or manipulating an algebraic equation. The following worked examples demonstrate standard problem-solving techniques for lower-secondary mathematics.

Example one involves calculating the gradient and y-intercept from a given graph and writing the equation of the line. Consider a line that crosses the y-axis at the point zero comma three and passes through the grid intersection point four comma eleven. To find the gradient, use the two points zero comma three and four comma eleven. The rise is the difference in y-coordinates, which is eleven minus three, equalling eight. The run is the difference in x-coordinates, which is four minus zero, equalling four. The gradient m is the rise divided by the run, so eight divided by four equals two. The y-intercept c is read directly from the y-axis intersection, which is positive three. Substituting these values into the general form gives the equation y = 2x + 3.

Example two involves rearranging a non-standard linear equation into slope-intercept form and identifying its features. Consider the equation 3x - 2y = 12. To find the gradient and y-intercept, y must be isolated. First, subtract 3x from both sides of the equation, resulting in negative 2y equals negative 3x plus twelve. Next, divide every term in the equation by negative two to isolate y entirely. Dividing negative 2y by negative two leaves y. Dividing negative 3x by negative two gives positive three over two times x. Dividing positive twelve by negative two gives negative six. The resulting equation is y = (3/2)x - 6. From this final form, the gradient m is three over two, and the y-intercept c is negative six.

Example three involves writing the equation of a line when given the gradient and a specific point. Find the equation of a line with a gradient of negative four that passes through the point one comma five. The general form is y = mx + c. Substitute the known gradient m equals negative four into the equation, giving y = -4x + c. To find the unknown y-intercept c, substitute the coordinates of the given point, where x is one and y is five, into the equation. This substitution yields five equals negative four multiplied by one plus c, which simplifies to five equals negative four plus c. Adding four to both sides gives c equals nine. Therefore, the complete equation of the line is y = -4x + 9.

Common Misconceptions and Errors

Learners studying linear relationships frequently encounter specific pitfalls that lead to incorrect calculations or misunderstandings of graphs. Awareness of these common errors helps in building robust mathematical habits.

One frequent mistake involves confusing the rise and the run during gradient calculations, placing the horizontal change over the vertical change instead of vertical over horizontal. This inversion flips the gradient value, turning a steep line into a shallow one or vice versa, and distorts the correct interpretation of the rate of change. Another common error occurs with negative signs when calculating rise and run. When a line slopes downwards, learners often forget that the change in y or x is negative, leading to an incorrect positive gradient for a declining line. Careful attention to the direction of movement along the coordinate axes prevents this sign error.

A third misconception relates to the y-intercept. Some learners assume that the y-intercept is always a positive number or that it is located where the line crosses the horizontal x-axis. In reality, the y-intercept is found exclusively on the vertical y-axis, and its value can be positive, negative, or zero. Finally, when rearranging equations into the form y = mx + c, learners often make arithmetic errors with signs when dividing or moving terms across the equals sign, particularly losing track of negative coefficients associated with the y variable. Methodical step-by-step algebra eliminates these avoidable mistakes.

मुख्य शब्द

Gradient
A numerical measure of the steepness and direction of a straight line, calculated as the rise divided by the run.
Y-intercept
The point where a straight line crosses the vertical y-axis, representing the initial value of the linear relationship where x is zero.
Rise
The vertical distance between two points on a line.
Run
The horizontal distance between two points on a line.
Linear Equation
An algebraic equation in which each term is either a constant or the product of a constant and a single variable, forming a straight line when graphed.
Slope-intercept form
The linear equation written in the standard format y = mx + c, where m is the gradient and c is the y-intercept.

हल किए गए उदाहरण

1Find the gradient and y-intercept of the line passing through the points zero comma three and four comma eleven, and write its equation.

हल दिखाएँ

Step 1: Identify the two points: (0, 3) and (4, 11).

Step 2: Calculate the rise by finding the difference in the y-coordinates: 11 minus 3 equals 8.

Step 3: Calculate the run by finding the difference in the x-coordinates: 4 minus 0 equals 4.

Step 4: Calculate the gradient m by dividing the rise by the run: m = 8 / 4 = 2.

Step 5: Identify the y-intercept c from the point (0, 3), where c equals 3.

Step 6: Substitute m and c into the slope-intercept form y = mx + c to get the final equation: y = 2x + 3.

Graph: the line y = 2x + 3.

2Rearrange the equation 3x - 2y = 12 into slope-intercept form and state its gradient and y-intercept.

हल दिखाएँ

Step 1: Write the original equation: 3x - 2y = 12.

Step 2: Subtract 3x from both sides to isolate the y term: -2y = -3x + 12.

Step 3: Divide every term by -2 to isolate y: y = (-3/-2)x + (12/-2).

Step 4: Simplify the fractions and signs: y = (3/2)x - 6.

Step 5: State the gradient m, which is the coefficient of x: m = 3/2.

Step 6: State the y-intercept c, which is the constant term: c = -6.

Graph: the line 3x - 2y = 12.

आम ग़लतफ़हमियाँ

ग़लतफ़हमी The gradient is calculated by dividing the run by the rise.

असल में The gradient is always calculated as the rise divided by the run. Dividing horizontal change by vertical change inverts the true slope value.

ग़लतफ़हमी The y-intercept is the point where the line crosses the horizontal x-axis.

असल में The y-intercept is located where the line crosses the vertical y-axis. The point where the line crosses the x-axis is called the x-intercept.

ग़लतफ़हमी A line that slopes downwards from left to right has a positive gradient.

असल में A line sloping downwards has a negative gradient because the vertical coordinate decreases as the horizontal coordinate increases.

ग़लतफ़हमी In the equation y = mx + c, the letter c represents the gradient.

असल में The letter m represents the gradient, while the letter c represents the y-intercept.

पाठ्यक्रम से मेल

Cambridge Lower Secondary Mathematics 0862

  • 8As.06 Recognise that equations of the form y = mx + c correspond to straight-line graphs, where m is the gradient and c is the y-intercept (integer values of m).
  • 9As.06 Understand that straight-line graphs can be represented by equations. Find the equation in the form y = mx + c or where y is given implicitly in terms of x (fractional, positive and negative gradients).