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Matematik

Constructions with Ruler and Compasses: Perpendicular and Angle Bisectors

Constructing the perpendicular bisector of a line segment and the bisector of an angle with ruler and compasses, with every arc shown; constructing a triangle from three sides.

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  1. 0:00 Constructions with Ruler and Compasses: Perpendicular and A…
  2. 1:23 Example 1: Triangle ABC has AB = 6 cm, BC = 5 cm and CA = 4…
  3. 1:54 Example 2: ABCD is a rhombus with side 5 cm and angle ABC =…
  4. 2:30 Example 3: Triangle ABC is constructed from AB = 7 cm, BC =…
  5. 3:00 Example 4: A circle with centre O and radius 5 cm is drawn…
  6. 3:25 Example 5: Three triangles have been constructed with ruler…
  7. 4:12 Example 6: Each triangle below was constructed with ruler a…
  8. 5:09 Example 7: Triangle ABC is constructed with AB = 8 cm, BC =…
  9. 5:46 Example 8: Triangle ABC is constructed with ruler and compa…
  10. 6:13 Common mistakes
  11. 6:38 Try it
  12. 6:57 Try it: In triangle ABC, AB = AC and angle BAC = 40 degrees…
  13. 7:20 Constructions with Ruler and Compasses: Perpendicular and A…

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Constructions with Ruler and Compasses: Perpendicular and Angle Bisectors: Slaid — slaid tajuk (pratonton)
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Constructions with Ruler and Compasses: Perpendicular and Angle Bisectors: Slaid — slaid pertama (pratonton)
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Constructions with Ruler and Compasses: Perpendicular and Angle Bisectors: Rancangan pengajaran — muka surat 1 (pratonton)
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Constructions with Ruler and Compasses: Perpendicular and Angle Bisectors: Lembaran kerja — muka surat 1 (pratonton)
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Apa yang anda akan pelajari

  • Construct the perpendicular bisector of a given line segment using a ruler and compasses.
  • Construct the bisector of a given angle using a ruler and compasses.
  • Construct a triangle when the lengths of all three sides are given.

Penerangan

Introduction to Geometric Constructions

Geometric construction is the drawing of lines, angles, and figures using only two tools: an unmarked ruler and a pair of compasses. In classical geometry, the ruler is used solely to draw straight lines, and the compasses are used to draw circles or arcs of circles. Measurements taken with numbers, such as using the centimetre scale on a ruler to measure a length, are avoided in pure constructions. Instead, distances are transferred directly from one part of a drawing to another using the fixed opening of the compasses. This approach ensures precision and relies entirely on geometric properties rather than numerical approximation.

Every construction relies on the fundamental property of a circle: all points on the circumference of a circle are at an exact, equal distance from its centre point, known as the radius. When two circles or arcs of the same radius intersect, the points of intersection hold specific geometric relationships to the centres of those circles. Lower-secondary geometry, aligned with Cambridge Lower Secondary and CBSE standards for ages 12 to 15, builds upon these foundational arc-drawing techniques to construct precise perpendiculars, bisectors, and triangles. Leaving all construction arcs visible on the page is essential because it demonstrates the method and proves that the construction was executed correctly.

Constructing the Perpendicular Bisector of a Line Segment

A perpendicular bisector is a line that divides a given line segment into two equal halves at a right angle of 90 degrees. To construct the perpendicular bisector of a line segment AB, start by placing the compass point on endpoint A. Open the compasses so that the distance between the compass point and the pencil tip is visibly greater than half the length of line segment AB. This condition is crucial; if the compass opening is less than half the length, the arcs drawn from each end will fail to intersect.

With this compass opening, draw an arc that extends above and below the line segment AB. Without changing the compass opening, move the compass point to endpoint B. Draw another arc that intersects the first arc at two points, one above line segment AB and one below line segment AB. Label the upper intersection point as point C and the lower intersection point as point D. Finally, use the unmarked ruler to draw a straight line passing through point C and point D. This straight line intersects line segment AB at its midpoint, let us call it point M. Line CD is perpendicular to line segment AB, meeting it at 90 degrees, and AM equals MB. Every point on the line CD is equidistant from endpoint A and endpoint B.

Constructing the Bisector of an Angle

An angle bisector is a ray that divides a given angle into two equal smaller angles. Consider angle ABC, where point B is the vertex and rays BA and BC form the arms of the angle. To construct the bisector of angle ABC, place the compass point on vertex B. Choose any convenient compass opening and draw an arc that cuts ray BA at a point, label it point P, and cuts ray BC at another point, label it point Q. The distance from vertex B to point P equals the distance from vertex B to point Q.

Next, place the compass point on point P and draw an arc in the interior of angle ABC. Without changing the compass opening, place the compass point on point Q and draw another arc that intersects the arc drawn from point P. Label this intersection point in the interior of the angle as point R. Take the unmarked ruler and draw a straight ray starting from vertex B and passing through point R. Ray BR is the angle bisector of angle ABC. Angle ABR is equal in measure to angle CBR, meaning that angle ABC has been divided into two identical halves.

Constructing Triangles from Three Sides

Compass and ruler constructions can be combined to draw entire geometric shapes, such as a triangle when the lengths of all three sides are known, often referred to as SSS construction. Suppose a triangle ABC needs to be constructed with side lengths AB = 7 cm, BC = 6 cm, and AC = 5 cm. Begin by drawing the base line segment AB of length 7 cm using the ruler, marking the endpoints carefully as A and B.

The next step is to find the position of the third vertex, point C. The distance from point A to point C must be 5 cm, and the distance from point B to point C must be 6 cm. Open the compasses to a radius of 5 cm by measuring against the ruler. Place the compass point on point A and draw an arc above line segment AB. Any point on this arc is exactly 5 cm away from point A.

Then, open the compasses to a radius of 6 cm using the ruler. Place the compass point on point B and draw another arc that intersects the first arc. The point where these two arcs cross is the required vertex C. Use the ruler to draw straight line segments from point A to point C, and from point B to point C. The resulting triangle ABC has sides of exactly 7 cm, 6 cm, and 5 cm. If the sum of the lengths of the two shorter sides is less than or equal to the length of the longest side, the arcs will not intersect, and no triangle can be formed.

Common Misconceptions and Troubleshooting

Learners often encounter difficulties during geometric constructions due to minor technical errors with compasses or misunderstandings of geometric requirements. One frequent error is altering the compass opening between drawing the first arc and the second arc when constructing a perpendicular bisector or an angle bisector. The compass opening must remain strictly constant once chosen for a specific set of intersecting arcs, because changing the radius destroys the symmetry required for accurate bisecting.

Another common mistake is setting the compass radius to less than half the line segment length when constructing a perpendicular bisector. If the radius is too small, the arcs drawn from the two endpoints will not cross each other in the middle, leaving the learner with no intersection points to join. Learners must ensure that the compass spread exceeds fifty percent of the segment length.

In triangle construction, a failure to intersect often stems from attempting to construct a triangle where the triangle inequality theorem is violated. The sum of any two side lengths of a triangle must strictly exceed the length of the third side. If a learner attempts to construct a triangle with sides 3 cm, 4 cm, and 8 cm, the arcs of radii 3 cm and 4 cm centered at opposite ends of an 8 cm base will fall short of each other. Checking side lengths before beginning the construction prevents this issue.

Istilah utama

Perpendicular Bisector
A line that divides a line segment into two equal parts at a right angle of 90 degrees.
Angle Bisector
A ray that divides an angle into two angles of equal measure.
Geometric Construction
The drawing of geometric figures, lines, and angles using only an unmarked ruler and a pair of compasses.
Arc
A connected section of the circumference of a circle, drawn using compasses during a construction.
Equidistant
At the exact same distance from two or more specified points or lines.

Contoh berjawapan

1Construct the perpendicular bisector of a line segment AB of length 8 cm, and state the length of AM where M is the midpoint.

Tunjukkan jawapan

Step 1: Draw a straight line segment AB of length 8 cm using the unmarked ruler, marking endpoints A and B.

Step 2: Open the compasses to a radius greater than half of 8 cm, for example 5 cm.

Step 3: Place the compass point on A and draw an arc extending above and below line segment AB.

Step 4: Keep the compass width at 5 cm, place the compass point on B, and draw an arc intersecting the first arc above and below line segment AB. Label the upper intersection point C and the lower intersection point D.

Step 5: Draw a straight line passing through C and D using the ruler. Label the point where line CD intersects line segment AB as point M.

Reasoning: By construction, triangle ACM is congruent to triangle BCM by SSS, which means angle AMC equals angle BMC. Since angles AMC and BMC lie on straight line AB and add up to 180 degrees, each angle is 90 degrees, making CD perpendicular to AB. Furthermore, AM equals MB because M is the midpoint.

Conclusion: AM = 4 cm because M divides the 8 cm segment AB into two equal halves.

2Construct the angle bisector of angle PQR which measures 60 degrees, and determine the measure of the resulting smaller angles.

Tunjukkan jawapan

Step 1: Draw angle PQR of measure 60 degrees with vertex at Q, using a protractor if setting up the angle, or use a 60-degree constructed angle.

Step 2: Place the compass point on vertex Q and draw an arc that intersects ray QP at point X and ray QR at point Y.

Step 3: Place the compass point on point X and draw an arc in the interior of angle PQR.

Step 4: Keep the same compass width, place the compass point on point Y, and draw an arc that intersects the arc from point X. Label this intersection point Z.

Step 5: Draw ray QZ from vertex Q through point Z using the unmarked ruler. Ray QZ is the angle bisector.

Reasoning: Triangle QXZ is congruent to triangle QYZ becauseQX equals QY (radii of the first arc), XZ equals YZ (radii of the intersecting arcs), and QZ is a shared common side. Therefore, angle XQZ equals angle YQZ.

Conclusion: The measure of angle XQZ and angle YQZ is 60 degrees divided by 2, which equals 30 degrees each.

Salah faham biasa

Mitos Changing the compass width between drawing arcs from different endpoints is acceptable.

Sebenarnya The compass width must remain identical when drawing intersecting arcs from two different points to maintain equal radii and ensure geometric symmetry.

Mitos Any three side lengths can be used to construct a triangle.

Sebenarnya The sum of the lengths of any two sides of a triangle must be strictly greater than the length of the third side, otherwise the arcs will not intersect.

Mitos A ruler can be used to measure exact lengths instead of compasses during a perpendicular bisector construction.

Sebenarnya Pure constructions require compasses to transfer distances and locate intersection points without relying on the ruler's measurement scale.