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Matemática · Ano 9, 8

Expanding Double Brackets

Multiplying two binomials term by term, collecting like terms, and checking the expansion by substitution.

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Capítulos deste vídeo
  1. 0:00 Expanding Double Brackets
  2. 1:17 Example 1: (x + 3)(x + 5)
  3. 2:32 Example 2: (y - 4)(y + 7)
  4. 3:49 Example 3: (2x - 3)(3x - 5)
  5. 5:03 Example 4: (x - 4)2
  6. 6:37 Common mistakes
  7. 7:01 Try it
  8. 7:18 Try it: (a - 3)(a + 6)
  9. 8:04 Expanding Double Brackets

O que vai aprender

  • Understand how to multiply two binomial expressions using the distributive law.
  • Collect and simplify like terms after expanding double brackets.
  • Check algebraic expansions using numerical substitution.

A explicação

Introduction to Binomials and the Distributive Law

In algebra, a binomial is an algebraic expression consisting of two terms connected by a plus or a minus sign, such as (x + 3) or (2y - 5). When two binomials are written side by side without any operation symbol between them, such as (x + 2)(x + 3), multiplication is implied. Expanding double brackets means multiplying every term in the first set of brackets by every term in the second set of brackets, and then simplifying the resulting expression.

The foundational rule that makes this possible is the distributive law of multiplication over addition. Consider multiplying a single term over a bracket, such as a(b + c), which results in ab + ac. When dealing with double brackets, such as (a + b)(c + d), the entire first bracket is treated as a single multiplier that is distributed over each term in the second bracket, or vice versa. This means (a + b)(c + d) can be rewritten as a(c + d) + b(c + d). Applying the single bracket expansion rules to both parts yields ac + ad + bc + bd. Every term in the left-hand bracket must interact with every term in the right-hand bracket. If each bracket contains two terms, the initial expansion will always produce four distinct terms before any simplification takes place. This process forms the bedrock of algebraic manipulation, enabling learners to transform factored forms into expanded polynomial forms.

Methodology: Term-by-Term Multiplication and FOIL

To ensure that no terms are missed during the expansion of double brackets, systematic methods are employed. One of the most common mnemonic devices used in lower-secondary mathematics is FOIL, which stands for First, Outer, Inner, Last. This acronym provides a structured order for multiplying the terms of two binomials, say (a + b)(c + d).

  1. First: Multiply the first term of each binomial together (a multiplied by c, giving ac).
  2. Outer: Multiply the outer terms of the binomial pair together (a multiplied by d, giving ad).
  3. Inner: Multiply the inner terms of the binomial pair together (b multiplied by c, giving bc).
  4. Last: Multiply the last term of each binomial together (b multiplied by d, giving bd).

Putting these together gives ac + ad + bc + bd. While FOIL is a helpful memory aid, it is important to understand that it is simply an application of the distributive law. Another robust method is the grid method, also known as the algebraic area model. In the grid method, a two-by-two table is constructed. The terms of the first binomial are placed along the top row, and the terms of the second binomial are placed down the left column. Each cell in the grid is then filled by multiplying its corresponding row and column headings. The final expanded expression is obtained by summing all the individual terms found inside the grid cells. Both methods yield identical results, and learners may choose the technique that best suits their working style.

Collecting Like Terms and Simplifying

Once the initial expansion of two binomials is complete, the resulting expression typically contains four terms. In many cases, two of these terms will be like terms, meaning they contain the exact same variable raised to the exact same power. Collecting like terms involves combining these individual quantities into a single term by adding or subtracting their numerical coefficients.

For example, consider an expansion that results in x2 + 3x + 2x + 6. Here, the terms 3x and 2x are like terms because they both feature the variable x to the power of one. To simplify the expression, their coefficients are added together: 3 + 2 = 5, yielding 5x. The x2 term and the constant term (+6) have no other like terms to combine with, so they remain as they are. The fully simplified expanded form is therefore x2 + 5x + 6. Learners must pay careful attention to the signs of the terms when collecting them. A negative sign attached to a coefficient belongs to that term and must be factored into any addition or subtraction. For instance, if the expansion produces -4x and +7x, combining them gives +3x. Diligent tracking of positive and negative numbers prevents common arithmetic errors during this crucial simplification phase.

Working with Negative Numbers and Coefficients

Expanding double brackets becomes more intricate when negative signs and coefficients greater than one are introduced. The fundamental principles remain identical, but signed number arithmetic must be applied rigorously at every multiplication step. When multiplying two terms, a positive multiplied by a positive gives a positive, a negative multiplied by a negative gives a positive, and a positive multiplied by a negative gives a negative.

Consider an expression containing negative terms, such as (x - 4)(x + 5). Applying the expansion method gives: First, x multiplied by x is x2. Outer, x multiplied by 5 is 5x. Inner, -4 multiplied by x is -4x. Last, -4 multiplied by 5 is -20. Putting these together gives x2 + 5x - 4x - 20. Collecting the like terms +5x and -4x results in +1x, which is written simply as +x. The final simplified expression is x2 + x - 20.

When coefficients are present in front of the variables, such as in (2x + 3)(3x - 1), each term must include both the coefficient and the variable during multiplication. First, 2x multiplied by 3x gives 6x2. Outer, 2x multiplied by -1 gives -2x. Inner, 3 multiplied by 3x gives 9x. Last, 3 multiplied by -1 gives -3. Combining the middle terms, -2x + 9x, gives +7x. The final expanded and simplified expression is 6x2 + 7x - 3. Careful adherence to the rules of indices and integer multiplication ensures accuracy in these more complex scenarios.

Checking Expansions by Substitution

In mathematics, verification is an essential habit. Because algebraic expansions involve multiple steps, mistakes with signs or arithmetic can easily occur. A reliable way to check whether an expanded expression is correct is through numerical substitution. This technique involves choosing a simple numerical value for the variable, substituting it into both the original unexpanded expression and the final expanded expression, and evaluating both. If both calculations yield the exact same numerical result, the expansion is very likely correct.

To avoid complications, substitution should generally be performed using small positive integers such as x = 2 or x = 3, while avoiding numbers like 0 or 1 which can sometimes mask errors because numbers like 1 multiplied by anything remains unchanged, or powers of 1 remain 1. For example, to check the expansion of (x + 2)(x + 3) which simplified to x2 + 5x + 6, choose x = 2.

Substitute x = 2 into the original factored expression: (2 + 2)(2 + 3) evaluates to (4)(5), which equals 20. Now substitute x = 2 into the expanded expression: (2)2 + 5(2) + 6 evaluates to 4 + 10 + 6, which also equals 20. Since both evaluations result in 20, the expansion has been verified successfully. If the two values do not match, an error occurred during either the multiplication or the collection of like terms, prompting a review of the working steps.

Common Misconceptions and Errors

Learners frequently encounter specific pitfalls when learning to expand double brackets. Recognizing these errors helps in developing strategies to avoid them. One widespread misconception is distributing only the first term of the left bracket across the right bracket, completely ignoring the second term. For instance, incorrectly expanding (x + 2)(x + 3) as x(x + 3) + 2, which misses half of the required multiplications. Every term in the first bracket must multiply every term in the second bracket.

Another frequent error relates to squaring binomials, such as writing (x + 3)2 as x2 + 9. Learners often mistakenly apply the exponent directly to each term inside the bracket. A squared bracket means the bracket is multiplied by itself: (x + 3)(x + 3). Expanding this correctly yields x2 + 3x + 3x + 9, which simplifies to x2 + 6x + 9. Notice the crucial middle term, 6x, which is omitted by the incorrect shortcut.

A third major area of difficulty involves sign errors when negative numbers are present. When multiplying a negative term by another term, learners sometimes forget that the product is positive, or they lose track of negative signs when collecting like terms. Writing out every intermediate step rather than attempting mental arithmetic for all four products significantly reduces these careless errors.

Termos-chave

Binomial
An algebraic expression consisting of two terms connected by a plus or minus sign.
Distributive Law
The algebraic rule stating that multiplying a number or term by a sum is equal to the sum of multiplying that term by each addend individually.
FOIL
A mnemonic for First, Outer, Inner, Last, representing the four products formed when multiplying two binomials.
Like Terms
Terms that contain the exact same variables raised to the exact same powers, which can be combined through addition or subtraction.
Numerical Substitution
The process of replacing variables with specific numbers to evaluate an expression or check the accuracy of an algebraic manipulation.

Exemplos resolvidos

1Expand and simplify the expression (x + 4)(x + 5).

Mostrar a solução

Step 1: Multiply the First terms of each binomial: x multiplied by x = x2.

Step 2: Multiply the Outer terms: x multiplied by 5 = 5x.

Step 3: Multiply the Inner terms: 4 multiplied by x = 4x.

Step 4: Multiply the Last terms: 4 multiplied by 5 = 20.

Step 5: Write out the unsimplified expansion: x2 + 5x + 4x + 20.

Step 6: Collect the like terms 5x and 4x to get 9x.

Step 7: Write the final simplified expression: x2 + 9x + 20.

2Expand and simplify the expression (x - 3)(x + 7).

Mostrar a solução

Step 1: Multiply the First terms: x multiplied by x = x2.

Step 2: Multiply the Outer terms: x multiplied by 7 = 7x.

Step 3: Multiply the Inner terms: -3 multiplied by x = -3x.

Step 4: Multiply the Last terms: -3 multiplied by 7 = -21.

Step 5: Write out the unsimplified expansion: x2 + 7x - 3x - 21.

Step 6: Collect the like terms +7x and -3x, which gives +4x.

Step 7: Write the final simplified expression: x2 + 4x - 21.

Ideias erradas comuns

Ideia errada Squaring a binomial by simply squaring each individual term, such as writing (x + 3)2 as x2 + 9.

Na verdade A squared binomial must be written out as two identical brackets, (x + 3)(x + 3), and fully expanded to include the middle terms, resulting in x2 + 6x + 9.

Ideia errada Multiplying only the first terms of each bracket and ignoring the outer, inner, and last combinations.

Na verdade Every term in the first bracket must be multiplied by every term in the second bracket, yielding four distinct terms before simplification.

Ideia errada Ignoring negative signs when multiplying or combining terms in an expansion.

Na verdade Negative signs belong to the term that follows them and must be included in every multiplication and when collecting like terms.

Alinhamento curricular

Cambridge Lower Secondary Mathematics 0862

  • 9Ae.02 Understand how to manipulate algebraic expressions including: – expanding the product of two algebraic expressions – applying the laws of indices – simplifying algebraic fractions.

CBSE Mathematics (Class 6-10)

  • 8:ALG:02 Algebraic Expressions and Identities